Programmer Guide/Command Reference/EVAL/exp: Difference between revisions
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{{DISPLAYTITLE:{{SUBPAGENAME}}}} | {{DISPLAYTITLE:{{SUBPAGENAME}}}} | ||
Exponential function | |||
;Usage: This function has several usage formats where the evaluation and the type of the result ''r'' depends on. The table below shows the possible usages and data types. | |||
:{| | |||
!usage !! evaluation !! data type of arguments !! data type of result ''r'' | |||
|- | |||
|<code>exp(<var>x</var>)</code> | |||
|''r''<sub>i,j</sub> = '''e''' ^ ''x''<sub>i,j</sub> | |||
| ''x'' can be any type | |||
| same type as ''x'' | |||
|- | |||
|<code>exp(<var>x</var>, <var>y</var><sub>S</sub>)</code> | |||
|''r''<sub>i,j</sub> = ''y''<sub>S</sub> ^ ''x''<sub>i,j</sub> | |||
| ''x'' can be any type<br>''y''<sub>S</sub> must be a scalar | |||
| same type as ''x'' | |||
|- | |||
|<code>exp(<var>x</var><sub>S</sub>, <var>y</var>)</code> | |||
|''r''<sub>i,j</sub> = ''y''<sub>i,j</sub> ^ ''x''<sub>S</sub> | |||
| ''x''<sub>S</sub> must be a scalar<br>''y'' can be any type | |||
| same type as ''y'' | |||
|- | |||
|<code>exp(<var>x</var>, <var>y</var>)</code> | |||
|''r''<sub>i,j</sub> = ''y''<sub>i,j</sub> ^ ''x''<sub>i,j</sub> | |||
| ''x'' must be a vector or matrix<br>''y'' must have the same type as ''x'' | |||
| same type as ''x'' and ''y'' | |||
|- | |||
|} | |||
:Note: The [[../#Operators|operator prefix '?']] combined with the [[../#Operators|power operator '^']] can be used instead of this function. | |||
;See also: [[../log|log, ln, lg]], [[../log2lin|lin2log, log2lin]] | |||
[[../#Functions|<function list>]] | |||
Latest revision as of 10:39, 21 April 2011
Exponential function
- Usage
- This function has several usage formats where the evaluation and the type of the result r depends on. The table below shows the possible usages and data types.
usage evaluation data type of arguments data type of result r exp(x)
ri,j = e ^ xi,j x can be any type same type as x exp(x, yS)
ri,j = yS ^ xi,j x can be any type
yS must be a scalarsame type as x exp(xS, y)
ri,j = yi,j ^ xS xS must be a scalar
y can be any typesame type as y exp(x, y)
ri,j = yi,j ^ xi,j x must be a vector or matrix
y must have the same type as xsame type as x and y
- Note: The operator prefix '?' combined with the power operator '^' can be used instead of this function.
- See also
- log, ln, lg, lin2log, log2lin