Programmer Guide/Command Reference/ARG: Difference between revisions
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:<code>/Setdefault</code> - mandatory option. | :<code>/Setdefault</code> - mandatory option. | ||
:<code>/Index=<var>iarg</var></code> - if iarg is specified, <code><var>var0</var></code> is set to the value of the argument referenced by <code><var>iarg</var></code>, <code><var>var1</var></code> is set to the value of the argument referenced by </code><var>iarg+1</var></code>, and so on. | :<code>/Index=<var>iarg</var></code> - if iarg is specified, <code><var>var0</var></code> is set to the value of the argument referenced by <code><var>iarg</var></code>, <code><var>var1</var></code> is set to the value of the argument referenced by </code><var>iarg+1</var></code>, and so on. | ||
;<code>ARG <var>arg0</var> [ <var>arg1</var> <var>arg2</var> ... ] /Replace [ /Variable ] [ /Index=<var>iarg</var> ]</code>: Replace the macro's arguments with the values specified in the <code>ARG</code> command (e.g. <var>arg0</var> will replace the first argument, <var>arg1</ | ;<code>ARG <var>arg0</var> [ <var>arg1</var> <var>arg2</var> ... ] /Replace [ /Variable ] [ /Index=<var>iarg</var> ]</code>: Replace the macro's arguments with the values specified in the <code>ARG</code> command (e.g. <var>arg0</var> will replace the first argument, <var>arg1</var> will replace the second argument, and so on). If <code>/Variable</code> is specified, the arguments to the <code>ARG</code> command will be taken as the names of variables whose <em>contents</em> will replace the respective macro arguments. If, on the other hand, </code>/Variable</code> is omitted, the arguments to <code>ARG</code> themselves will replace the respective macro arguments. | ||
:If option <code>/Index=<var>iarg</var></code> is specified, with <var>iarg</var> being an integer not less than zero, the first macro argument to be replaced will be the (<var>iarg</var>+1)th macro argument, that is the macro argument whose zero-based index is <var>iarg</var>. If "/Index" is omitted, replacement will start with the first macro argument. | :If option <code>/Index=<var>iarg</var></code> is specified, with <var>iarg</var> being an integer not less than zero, the first macro argument to be replaced will be the (<var>iarg</var>+1)th macro argument, that is the macro argument whose zero-based index is <var>iarg</var>. If "/Index" is omitted, replacement will start with the first macro argument. | ||
:;Example: If a macro is called with the three string arguments "one", "two", and "three", after executing <code>ARG /Replace /Index=1 'SPONGE BOB'</code>, the macro will behave as if called with the three string arguments "one", "SPONGE BOB", and "THREE". | :;Example: If a macro is called with the three string arguments "one", "two", and "three", after executing <code>ARG /Replace /Index=1 'SPONGE BOB'</code>, the macro will behave as if called with the three string arguments "one", "SPONGE BOB", and "THREE". |
Revision as of 21:05, 10 March 2011
ARG
#nArgs := ARG
- Returns the number of arguments parsed to the current macro.
#argX := ARG iArg
- Returns the value of the argument addressed by the zero-based index iArg.
#nCopiedArgs := ARG var0 var1 var2 /Variable [ /Index=iarg ] [ /Delete ]
- Copies the values of the arguments passed to the macro to the respective variables
var0
,var1
, and so on. - If you supply more variables than there are macro arguments, the surplus variables will not be touched, keeping whatever value they had before executing the
ARG
command. If this is not what you want, you may use the/Delete
argument: With/Delete
being supplied, the contents of all surplus variables will be cleared. - If you supply less variables than there are arguments, the surplus arguments will be ignored.
varX
- the name of the variable to store the arguments in. If/Index
does not specify otherwise, the value of argument 0 is stored in var0, the value of argument 1 is stored in var1, and so on./Variable
- mandatory option./Delete
- delete contents of variables first. If you do not use this option, any surplus variables, i.e. variables without a corresponding macro argument, will be left untouched, meaning that they will keep whatever value they had before executing theARG
command./Index=iarg
- if iarg is specified,var0
is set to the value of the argument referenced byiarg
,var1
is set to the value of the argument referenced by iarg+1, and so on.#nCopiedArgs := ARG arg0 def0 [ arg1 def1 ... ] /Variable /Setdefault [ /Index=iarg ]
- Sets the variables specified to the values of the arguments passed to the macro, using the specified default values if the argument is missing, and returns the number of copied arguments. In all other respects, this variant of the
ARG
command works just like the aformentionedARG /Variable
. varX
- the name of the variable to store the arguments in. If/Index
does not specify otherwise, the value of argument 0 is stored in var0, the value of argument 1 is stored in var1, and so on./Variable
- mandatory option./Setdefault
- mandatory option./Index=iarg
- if iarg is specified,var0
is set to the value of the argument referenced byiarg
,var1
is set to the value of the argument referenced by iarg+1, and so on.ARG arg0 [ arg1 arg2 ... ] /Replace [ /Variable ] [ /Index=iarg ]
- Replace the macro's arguments with the values specified in the
ARG
command (e.g. arg0 will replace the first argument, arg1 will replace the second argument, and so on). If/Variable
is specified, the arguments to theARG
command will be taken as the names of variables whose contents will replace the respective macro arguments. If, on the other hand, /Variable is omitted, the arguments toARG
themselves will replace the respective macro arguments. - If option
/Index=iarg
is specified, with iarg being an integer not less than zero, the first macro argument to be replaced will be the (iarg+1)th macro argument, that is the macro argument whose zero-based index is iarg. If "/Index" is omitted, replacement will start with the first macro argument.- Example
- If a macro is called with the three string arguments "one", "two", and "three", after executing
ARG /Replace /Index=1 'SPONGE BOB'
, the macro will behave as if called with the three string arguments "one", "SPONGE BOB", and "THREE". - Note
- Replacing macro arguments will not change the values of any variables the macro arguments have been read into. If you want to change these, too, you need to redo argument parsing.
ARG arg0 [ arg1 arg2 ... ] /Nsert [ /Variable ] [ /Index=iarg ]
This command works like the "ARG
/Replace" command with the difference that it does not replace the old argument, but it shifts it (and all further arguments) to the right.
Remark: This option is called "/Nsert" because the letter "i" was already used for the "/Index" argument. (Both "insert" and "index" start with an "i", you see.)
See the script argument_parsing_example.sts
for working examples.