Programmer Guide/Command Reference/EVAL/smooth: Difference between revisions

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;Description:
;Description:
The smoothing function is selected by the argument ''type''. The smoothed value ''xs''[i] is computed from the data values ''x''[i-m] to ''x''[i+m]. The general form of the smoothing function is:
The smoothing function is selected by the argument ''type''. The smoothed value ''xs''[i] is computed from the data values ''x''[i-m] to ''x''[i+m]. The general form of the smoothing function is:
<math>\sum{j=i-m,i+m}\prod{x[j],w[j]}</math>
<math>\sum_j=i-m_i+m{x_j.w_j}</math>
{|class="einrahmen"  
{|class="einrahmen"  
!''type'' !! smoothing algorithm !! ''xs''[i] =
!''type'' !! smoothing algorithm !! ''xs''[i] =

Revision as of 12:38, 13 April 2011

Apply a smoothing to the vector x.

Usage
smooth(x {, type=0 {, m=1 {, s=1}}})
x
data vector
m
smoothing length; 0 < m <= nrow(x)/2 (default=1)
type
selects the smoothing algorithm (default=0)
soutput step size; 0 < s <= nrow(x)/2 (default=1)
Description

The smoothing function is selected by the argument type. The smoothed value xs[i] is computed from the data values x[i-m] to x[i+m]. The general form of the smoothing function is: {\displaystyle \sum _{j}=i-m_{i}+m{x_{j}.w_{j}}}

type smoothing algorithm xs[i] =
0 average (x[i-m]+x[i-m+1]+..+x[i]+..+x[i+m-1]+ x[i+m]) / (2*m+1)
0 average with reciprocal weights (x[i-m]/(m+1)x[i-m+1]/m+..+x[i]+..+x[i+m-1]/m+ x[i+m]/(m+1)) / (1 + 2*m+1)
Result
A vector r with nrow(x)/s elements. The value r[j] is set to the value xs[j*s] of the smoothed data vector.

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