Programmer Guide/Command Reference/ARG: Difference between revisions
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Revision as of 17:31, 18 November 2010
ARG
#nArgs := ARG
Returns the number of arguments parsed to the current macro.
#argX := ARG iArg
Returns the value of the argument addressed by the zero-based index iArg.
ARG var0 var1 var2 /V [ /I=iarg ] [ /D ]
Sets the variables specified to the values of the arguments passed to the macro, and returns the number of copied arguments.
varX - the name of the variable to store the arguments in. If /I does not specify otherwise, the value of argument 0 is stored in var0.
/V - mandatory option.
/D - delete contents of variables first.
/I=iarg - if iarg is specified, var0 is set to the value of the argument referenced by iarg.
#nCopiedArgs := ARG arg0 def0 [ arg1 def1 ... ] /V [ /I=iarg ] /S
Sets the variables specified to the values of the arguments passed to the macro, using the specified default values if the argument is missing, and returns the number of copied arguments.
/V - mandatory option.
/S - mandatory option.
/I=iarg - if iarg is specified, var0 is set to the value of the argument referenced by iarg.
ARG arg0 [ arg1 arg2 ... ] /Replace [ /Variable ] [ /Index=iarg ]
Replace the macro's arguments with the values specified in the ARG
command (e.g. arg0 will replace the first argument). If "/Variable" is specified, the arguments to the ARG
command will be taken as the names of variables whose *contents* will replace the respective macro arguments. If, on the other hand, "/Variable" is omitted, the arguments to ARG
themselves will replace the respective macro arguments.
If option "/Index=iarg" is specified, with iarg being an integer not less than zero, the first macro argument to be replaced will be the (iarg+1)th macro argument, that is the macro argument whose zero-based index is iarg. If "/Index" is omitted, replacement will start with the first macro argument.
Example: If a macro is called with the three string arguments "one", "two", and "three", after executing "ARG /Replace /Index=1 'SPONGE BOB'
", the macro will behave as if called with the three string arguments "one", "SPONGE BOB", and "THREE".
Note: Replacing macro arguments will *not* change the values of any variables the macro arguments have been read into. If you want to change these, too, you need to redo argument parsing.
ARG arg0 [ arg1 arg2 ... ] /Nsert [ /Variable ] [ /Index=iarg ]
This command works like the "ARG
/Replace" command with the difference that it does not replace the old argument, but it shifts it (and all further arguments) to the right.
Remark: This option is called "/Nsert" because the letter "i" was already used for the "/Index" argument. (Both "insert" and "index" start with an "i", you see.)
See the script argument_parsing_example.sts
for working examples.